Asked by Emma
one nucleus decays by emitting an alpha aprticle of KE x Mev. if such alpha particle goes directly toward another nucleus of the same atom, what is the distance of closest approach?
i don't quite get this question.am i supposed to find r since r=r0A^(1/3)? but what is with the KE?
i don't quite get this question.am i supposed to find r since r=r0A^(1/3)? but what is with the KE?
Answers
Answered by
bobpursley
set the KE initial equal to the PE in relation to the second nucleus. Then solve for distance to the nucleus. This would be a first approximation.
Answered by
Emma
so do you mean total E=KE+PE?
i think i can use the r=r0A^(1/3) to find the radius of the nucleus, but i am still not sure what i should do with the E and wavelength.
confused.
i think i can use the r=r0A^(1/3) to find the radius of the nucleus, but i am still not sure what i should do with the E and wavelength.
confused.
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