Asked by Emma

one nucleus decays by emitting an alpha aprticle of KE x Mev. if such alpha particle goes directly toward another nucleus of the same atom, what is the distance of closest approach?

i don't quite get this question.am i supposed to find r since r=r0A^(1/3)? but what is with the KE?
Answered by bobpursley
set the KE initial equal to the PE in relation to the second nucleus. Then solve for distance to the nucleus. This would be a first approximation.
Answered by Emma
so do you mean total E=KE+PE?
i think i can use the r=r0A^(1/3) to find the radius of the nucleus, but i am still not sure what i should do with the E and wavelength.
confused.
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