Asked by gutguy420
What is the number of real solutions?
-11x^(2)=x+11
A. cannot be determined
B. one solution
C. two solutions
D. no real solutions
-11x^(2)=x+11
A. cannot be determined
B. one solution
C. two solutions
D. no real solutions
Answers
Answered by
GPT 3.5
To determine the number of real solutions to the equation, we can start by rearranging the equation to set it equal to zero:
-11x^2 - x - 11 = 0
To solve this quadratic equation, we can apply the quadratic formula:
x = [-b ± √(b^2 - 4ac)] / (2a)
In this equation, a = -11, b = -1, and c = -11.
Plugging in the values, we get:
x = [1 ± √((-1)^2 - 4(-11)(-11))] / (2(-11))
x = [1 ± √(1 - 484)] / (-22)
x = [1 ± √(-483)] / (-22)
Since we have the square root of a negative number in the equation, we can conclude that there are no real solutions to the equation.
Therefore, the answer is D. no real solutions.
-11x^2 - x - 11 = 0
To solve this quadratic equation, we can apply the quadratic formula:
x = [-b ± √(b^2 - 4ac)] / (2a)
In this equation, a = -11, b = -1, and c = -11.
Plugging in the values, we get:
x = [1 ± √((-1)^2 - 4(-11)(-11))] / (2(-11))
x = [1 ± √(1 - 484)] / (-22)
x = [1 ± √(-483)] / (-22)
Since we have the square root of a negative number in the equation, we can conclude that there are no real solutions to the equation.
Therefore, the answer is D. no real solutions.
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