To find the equation of a line that is perpendicular to the line y = 3x + 2 and passes through the point (6, -8), we can first find the slope of the given line. The slope of a line in the form y = mx + b is equal to m. Therefore, for the line y = 3x + 2, the slope is 3.
A line that is perpendicular to another line has a slope that is the negative reciprocal of the slope of the given line. Therefore, the slope of the new line is -1/3.
Using the point-slope form of a linear equation, which is y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope, we can substitute the values into the equation:
y - (-8) = (-1/3)(x - 6)
y + 8 = (-1/3)x + 2
y = (-1/3)x + 2 - 8
y = (-1/3)x - 6
Therefore, the equation of the line that contains the new wall is y = (-1/3)x - 6.
Plans for a stadium are drawn on a coordinate grid. One wall lies on the line y = 3x + 2. A perpendicular wall passes through the point (6, -8. Write the equation of the line that contains the new wall
y=-1/3x-6
y=3x-26
y=1/3x-10
y=-3x-14
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