What is an equation in slope-intercept form for the line that passes through the points (1, –3) and (3, 1)? (1 point) Responses y = 3x + 1 y = 3 x + 1 y = x – 3 y = x – 3 y = 2x + 5 y = 2 x + 5 y = 2x – 5

Answer 1

To find the equation of the line in slope-intercept form, we need to find the slope and the y-intercept.

First, let's find the slope (m) using the formula:
m = (y2 - y1) / (x2 - x1)

Using the points (1, -3) and (3, 1), we can plug in the values into the formula:
m = (1 - (-3)) / (3 - 1)
m = 4 / 2
m = 2

Now that we have the slope, we can use the slope-intercept form of a linear equation which is:
y = mx + b

We have the value of m, so let's plug it in:
y = 2x + b

To find the y-intercept (b), we can plug in the coordinates of one of the points into the equation and solve for b.

Using the point (1, -3), we have:
-3 = 2(1) + b
-3 = 2 + b
b = -3 - 2
b = -5

Therefore, the equation of the line in slope-intercept form that passes through the points (1, -3) and (3, 1) is:
y = 2x - 5