Solve the inequality

Question

5f+7<22

Answer 1

To solve the inequality, we begin by subtracting 7 from both sides of the equation:

5f + 7 - 7 < 22 - 7

This simplifies to:

5f < 15

Next, we divide both sides of the equation by 5 to isolate the variable f:

(5f)/5 < 15/5

This simplifies to:

f < 3

Therefore, the solution to the inequality 5f + 7 < 22 is f < 3.

Answer 2

Solve the inequality
6n-3>-18

Answer 3

To solve the inequality, we begin by adding 3 to both sides of the equation:

6n - 3 + 3 > -18 + 3

This simplifies to:

6n > -15

Next, we divide both sides of the equation by 6 to isolate the variable n:

(6n)/6 > (-15)/6

This simplifies to:

n > -2.5

Therefore, the solution to the inequality 6n - 3 > -18 is n > -2.5.

Answer 4

An isosceles triangle has at least two congruent sides. The
perimeter of a certain isosceles triangle is at most 12 in. The
length of each of the two congruent sides is 5 in. What are the
possible lengths of the remaining side?
(1 point)
s>5 but less than 12
s<12 but greater than 0
s<10 but greater than 0
s<2 but greater than 0

Answer 5

Given that the perimeter of the isosceles triangle is at most 12 in and the length of each of the two congruent sides is 5 in, let's denote the remaining side as 's'.

The perimeter of a triangle can be found by adding the lengths of all three sides. In this case, we have two congruent sides with a length of 5 in each, so the sum of both these sides is 5 in + 5 in = 10 in.

To find the possible lengths of the remaining side, we subtract the sum of the two congruent sides from the maximum perimeter:

12 in - 10 in = 2 in

Therefore, the possible lengths of the remaining side are s < 2 but greater than 0.