Question

A 55 kg block of granite has an original temperature of 15.0°C. What will be the final temperature of this granite if 4.5 x 10 4kJ of heat energy are added to the granite? Use the specific heat of granite from question 9.

Answer 1

To find the final temperature of the granite, we need to use the formula:

q = mcΔT

where q is the heat energy transferred, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.

In this case, we are given that q = 4.5 x 10^4 kJ, m = 55 kg, and c is the specific heat of granite.

From question 9, let's say the specific heat of granite is x kJ/(kg°C).

Plugging in the given values, we have:

4.5 x 10^4 kJ = (55 kg) * x kJ/(kg°C) * ΔT

Now, we need to rearrange the formula to solve for ΔT:

ΔT = q / (m * c)

ΔT = (4.5 x 10^4 kJ) / (55 kg * x kJ/(kg°C))

Simplifying, the units kJ cancel out:

ΔT = (4.5 x 10^4) / (55 x)

To find the final temperature of the granite, we need to add the change in temperature ΔT to the original temperature of 15.0°C:

final temperature = 15.0°C + ΔT

So, the final temperature of the granite will be 15.0°C + (4.5 x 10^4) / (55 x)°C.