Question
3. Suppose β = {1,2,3, β¦ } is the universal set and π΄ = {π₯: π₯ β€ 6}, π΅ = {π₯: 4 β€ π₯ β€ 9} and
πΆ = {2,3,5,7,8}. Then, find π΄ β© (π΅ β πΆ).
πΆ = {2,3,5,7,8}. Then, find π΄ β© (π΅ β πΆ).
Answers
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GPT 3.5
To find π΄ β© (π΅ β πΆ), we need to first find the symmetric difference, π΅ β πΆ.
The symmetric difference, π΅ β πΆ, is defined as the set of elements that are in π΅ or πΆ, but not both.
From the given sets, π΅ = {4,5,6,7,8,9} and πΆ = {2,3,5,7,8}.
To find π΅ β πΆ, we need to find the elements that are in π΅ or πΆ but not in both:
π΅ β πΆ = {4,5,6,7,8,9} β {2,3,5,7,8}
= {4,6,9} β {2,3}
Now we can find the intersection of this symmetric difference with set π΄.
π΄ = {π₯: π₯ β€ 6} = {1,2,3,4,5,6}
π΄ β© (π΅ β πΆ) = {1,2,3,4,5,6} β© {4,6,9}
= {4,6}
Therefore, π΄ β© (π΅ β πΆ) = {4,6}.
The symmetric difference, π΅ β πΆ, is defined as the set of elements that are in π΅ or πΆ, but not both.
From the given sets, π΅ = {4,5,6,7,8,9} and πΆ = {2,3,5,7,8}.
To find π΅ β πΆ, we need to find the elements that are in π΅ or πΆ but not in both:
π΅ β πΆ = {4,5,6,7,8,9} β {2,3,5,7,8}
= {4,6,9} β {2,3}
Now we can find the intersection of this symmetric difference with set π΄.
π΄ = {π₯: π₯ β€ 6} = {1,2,3,4,5,6}
π΄ β© (π΅ β πΆ) = {1,2,3,4,5,6} β© {4,6,9}
= {4,6}
Therefore, π΄ β© (π΅ β πΆ) = {4,6}.