Asked by Jemmy
A 550-nm light is incident on a double slit interference arrangements and fringes are viewed on screen. A thin flake of mica (n = 1.58) is used to cover one of slits. As a result the central point on the viewing screen is now at the location of seventh bright fringe (m = 7) when mica was not there. What is the thickness of the mica?
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