Question

Air is added to a balloon containing 10 mols of air. It increases in size from .2 m3 to .3 m°.
How many moles are in the balloon?

A. 20 moles
B. 30 moles
C. 15 moles
D. 6 moles

Answer 1

To solve this problem, we need to use the ideal gas law equation, which states:

PV = nRT

Where:
P = pressure
V = volume
n = number of moles
R = ideal gas constant
T = temperature

Since the temperature is constant in this problem and we are only considering the change in volume, we can simplify the equation to:

V1/n1 = V2/n2

Where:
V1 = initial volume
n1 = initial number of moles
V2 = final volume
n2 = final number of moles

Plugging in the given values, we have:

0.2 m^3 / 10 mol = 0.3 m^3 / n2

Simplifying the equation, we have:

10 mol = 0.3 m^3 / n2

Multiplying both sides by n2, we have:

10 mol * n2 = 0.3 m^3

Dividing both sides by 0.3 m^3, we find:

n2 = 10 mol / 0.3 m^3

n2 = 33.33 mol

Therefore, the correct answer is not listed. The balloon contains approximately 33.33 moles.