To solve this problem, we can use the ideal gas law, which states:
\[PV = nRT\]
Where:
P = pressure (in Pa)
V = volume (in m^3)
n = number of moles of gas
R = gas constant (8.314 J/(mol·K))
T = temperature (in Kelvin)
Assuming that the volume of the soda can remains constant, we can rewrite the ideal gas law as:
\[P_1/T_1 = P_2/T_2\]
In this case, the initial pressure and temperature are given as P_1 = 120000 Pa and T_1 = 240 K, respectively. The final temperature is T_2 = 300 K, and we need to find the final pressure P_2.
Plugging in the values into the equation:
\[P_2 = P_1 \cdot \frac{T_2}{T_1}\]
\[P_2 = 120000 \cdot \frac{300}{240} = 150000 \, \text{Pa}\]
Therefore, the new pressure in the can is 150000 Pa. The correct answer is A.
A soda can with 120000 Pa of pressure is heated from 240 K to 300K in hot water. What is the new pressure in the can?
A. 150000 Pa
B. 240000 Pa
C. 96000 Pa
D. 120000 Pa
Show your work, correct answers only plz.
1 answer