Starting from 130 feet away, a person on bicycle rides towards a checkpoint and then passes it. The rider is traveling at a constant rate of 25 feet per second. The distance between the bicycle and the checkpoint is given by the equation d=130-25. At what times is the bike 15 feet away from the checkpoint?

Question

(1 point)
4.6 sec and 9.2 sec
2.9 sec and 5.8 sec
4.6 sec and 5.8 sec
2.9 sec and 3.3 sec

Answer 1

To find the times when the bike is 15 feet away from the checkpoint, we need to solve the equation:

d = 15

Substituting the given equation:

130 - 25t = 15

Simplifying the equation:

-25t = -115

Dividing by -25:

t = 4.6

Therefore, the bike is 15 feet away from the checkpoint at 4.6 seconds.