Write y - 2 = 3/2 (x+2) in slope Intercept form

Answer 1

To write the equation in slope-intercept form (y = mx + b), we need to isolate y on one side of the equation.

Starting with y - 2 = 3/2(x + 2):

Distribute the 3/2 to both terms inside the parentheses:
y - 2 = 3/2 * x + 3/2 * 2

Simplify the right side:
y - 2 = 3/2 * x + 3

Add 2 to both sides of the equation to isolate y:
y = 3/2 * x + 3 + 2

Simplify:
y = 3/2 * x + 5

The equation in slope-intercept form is y = 3/2x + 5.