The equation is 2(g-10)-g=g-20.
Expanding the equation, we have 2g - 20 - g = g - 20.
Simplifying, we get g - 20 = g - 20.
By subtracting g from both sides, we obtain -20 = -20.
Since -20 is equal to -20, this equation is always true, meaning that any value of g is a solution.
Therefore, there are infinitely many solutions to this equation.
How many solutions do the following equations have?
2(g-10)-g=g-20
1 answer