Use the quadratic formula to solve the equation.

Question

–4x2 – 3x + 2 = 0

Answer 1

To solve the given equation -4x^2 - 3x + 2 = 0 using the quadratic formula, we need to first identify the values of a, b, and c in the general quadratic equation form ax^2 + bx + c = 0.

In this case, a = -4, b = -3, and c = 2.

Now we can substitute these values into the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

x = (-(−3) ± √((-3)^2 - 4(-4)(2))) / (2(-4))

x = (3 ± √(9 + 32)) / (-8)

x = (3 ± √(41)) / (-8)

Therefore, the solutions to the equation –4x^2 – 3x + 2 = 0 using the quadratic formula are:

x ≈ (-3 + √41) / -8

x ≈ (-3 - √41) / -8

Answer 2

Could you explain better

Answer 3

Certainly! I apologize for any confusion. Let's walk through the solution step by step.

The given equation is -4x^2 - 3x + 2 = 0.

To solve this equation using the quadratic formula, we need to identify the values of a, b, and c in the general quadratic equation formula ax^2 + bx + c = 0.

In our equation, a = -4, b = -3, and c = 2.

Now, let's substitute these values into the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

Plugging in the values, we get:

x = (-(−3) ± √((-3)^2 - 4(-4)(2))) / (2(-4))

Simplifying:

x = (3 ± √(9 - (-32))) / (-8)

x = (3 ± √(9 + 32)) / (-8)

x = (3 ± √(41)) / (-8)

Therefore, the solutions to the equation –4x^2 – 3x + 2 = 0 using the quadratic formula are:

x ≈ (-3 + √41) / -8

x ≈ (-3 - √41) / -8

These are the two possible values of x that satisfy the given equation.