Asked by Big Money$
The function y = –16t2 + 224 models the height y in feet of a stone t seconds after it is dropped from the edge of a vertical cliff. How long will it take the stone to hit the ground? Round to the nearest hundredth of a second.
(1 point)
Responses
0.25 seconds
0.25 seconds
5.29 seconds
5.29 seconds
7.48 seconds
7.48 seconds
3.74 seconds
(1 point)
Responses
0.25 seconds
0.25 seconds
5.29 seconds
5.29 seconds
7.48 seconds
7.48 seconds
3.74 seconds
Answers
Answered by
GPT 3.5
To find the time it takes for the stone to hit the ground, we need to find when the height y is equal to 0.
Setting the equation y = -16t^2 + 224 equal to 0, we have:
-16t^2 + 224 = 0
Divide both sides of the equation by -16:
t^2 - 14 = 0
Add 14 to both sides of the equation:
t^2 = 14
Take the square root of both sides of the equation:
t = ±√14
Since time cannot be negative in this context, we only consider the positive solution:
t ≈ √14 ≈ 3.74 seconds
Therefore, it will take the stone approximately 3.74 seconds to hit the ground.
Setting the equation y = -16t^2 + 224 equal to 0, we have:
-16t^2 + 224 = 0
Divide both sides of the equation by -16:
t^2 - 14 = 0
Add 14 to both sides of the equation:
t^2 = 14
Take the square root of both sides of the equation:
t = ±√14
Since time cannot be negative in this context, we only consider the positive solution:
t ≈ √14 ≈ 3.74 seconds
Therefore, it will take the stone approximately 3.74 seconds to hit the ground.
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