To find the solutions of the quadratic equation 4x^2 + 34x + 60 = 0, we need to use the quadratic formula.
The quadratic formula states that for an equation in the form ax^2 + bx + c = 0, the solutions are given by:
x = (-b ± √(b^2 - 4ac)) / (2a)
For the given equation, a = 4, b = 34, and c = 60. Let's substitute these values into the quadratic formula:
x = (-(34) ± √((34)^2 - 4(4)(60))) / (2(4))
Simplifying:
x = (-34 ± √(1156 - 960)) / 8
x = (-34 ± √196) / 8
x = (-34 ± 14) / 8
This gives us two solutions:
x1 = (-34 + 14) / 8 = -20 / 8 = -2.5
x2 = (-34 - 14) / 8 = -48 / 8 = -6
Therefore, the solutions to the quadratic equation 4x^2 + 34x + 60 = 0 are x = -2.5 and x = -6.
What are the solutions of the quadratic equation?
4x2 + 34x + 60 = 0
1 answer