The correct equation, in standard form, of the parabola that models the values in the table is:
y = 4x^2 + 5x - 6
What is the equation, in standard form, of a parabola that models the values in the table?
x
–2
0
4
f(x)
0
–6
78
(1 point)
Responses
y = 6x2 + 5x – 4
y = 6 x 2 + 5 x – 4
y = –4x2 – 5x + 6
y = –4 x 2 – 5 x + 6
y = 5x2 + 4x – 6
y = 5 x 2 + 4 x – 6
y = 4x2 + 5x – 6
1 answer