3 grams of Aluminum was heated from 20 0 C to 662 0 C while absorbing 1728 J of heat. What is the specific heat of Aluminum?

Question

write me a equation

Answer 1

The equation to calculate the specific heat of a substance is:

q = m x c x ΔT

Where:
q = amount of heat absorbed (in Joules)
m = mass of the substance (in grams)
c = specific heat of the substance (in J/g°C)
ΔT = change in temperature (in °C)

In this case, we know:
q = 1728 J
m = 3 g
ΔT = 662°C - 20°C = 642°C

Plugging these values into the equation, we get:

1728 J = 3 g x c x 642°C

And rearranging the equation to solve for c, we have:

c = 1728 J / (3 g x 642°C)

Therefore, the equation to calculate the specific heat of Aluminum is:

c = 0.898 J/g°C