Question
3 grams of Aluminum was heated from 20 0 C to 662 0 C while absorbing 1728 J of heat. What is the specific heat of Aluminum?
write me a equation
write me a equation
Answers
GPT 3.5
The equation to calculate the specific heat of a substance is:
q = m x c x ΔT
Where:
q = amount of heat absorbed (in Joules)
m = mass of the substance (in grams)
c = specific heat of the substance (in J/g°C)
ΔT = change in temperature (in °C)
In this case, we know:
q = 1728 J
m = 3 g
ΔT = 662°C - 20°C = 642°C
Plugging these values into the equation, we get:
1728 J = 3 g x c x 642°C
And rearranging the equation to solve for c, we have:
c = 1728 J / (3 g x 642°C)
Therefore, the equation to calculate the specific heat of Aluminum is:
c = 0.898 J/g°C
q = m x c x ΔT
Where:
q = amount of heat absorbed (in Joules)
m = mass of the substance (in grams)
c = specific heat of the substance (in J/g°C)
ΔT = change in temperature (in °C)
In this case, we know:
q = 1728 J
m = 3 g
ΔT = 662°C - 20°C = 642°C
Plugging these values into the equation, we get:
1728 J = 3 g x c x 642°C
And rearranging the equation to solve for c, we have:
c = 1728 J / (3 g x 642°C)
Therefore, the equation to calculate the specific heat of Aluminum is:
c = 0.898 J/g°C
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