Asked by Landon
A beam of unknown charged particles passes at right angle to the direction of magnetic field of 9.0 10-2 T. If the speed of the particles is 3.0 104 m/s and force experienced by a particle is 8.64 10-16 N, how many electric charges are carried by one particle?
{Force} = F = {Charge}*{Velocity}*{Magnetic Field Strength} = Q*V*B
----> {Charge} = Q = F/(V*B)
----> {Charge} = (8.64e-16)/((3.0e+4)*(9.0e-2))
----> {Charge} = 3.2e-19 Coulombs
----> {# Electric Charges} = {Charge}/(1.6e-19)
----> {# Electric Charges} = (3.2e-19)/(1.6e-19)
----> {# Electric Charges Per Particle} = 2
{Force} = F = {Charge}*{Velocity}*{Magnetic Field Strength} = Q*V*B
----> {Charge} = Q = F/(V*B)
----> {Charge} = (8.64e-16)/((3.0e+4)*(9.0e-2))
----> {Charge} = 3.2e-19 Coulombs
----> {# Electric Charges} = {Charge}/(1.6e-19)
----> {# Electric Charges} = (3.2e-19)/(1.6e-19)
----> {# Electric Charges Per Particle} = 2
Answers
Answered by
bobpursley
correct thinking.
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