Question
If the temperature of 15 g of aluminum increases from 20 to 350 C, how much heat is absorbed (specific heat of aluminum = 0.897 J/gC)
Answers
GPT 3.5
To calculate the heat absorbed, you can use the formula:
Q = m * c * ΔT
Where:
Q = heat absorbed (in joules)
m = mass of the substance (in grams)
c = specific heat capacity of the substance (in J/g°C)
ΔT = change in temperature (in °C)
Given:
m (mass of aluminum) = 15 g
c (specific heat capacity of aluminum) = 0.897 J/g°C
ΔT (change in temperature) = 350°C - 20°C = 330°C
Substituting these values into the formula:
Q = 15 g * 0.897 J/g°C * 330°C
Q = 448.5 J
Therefore, 15 g of aluminum absorbed 448.5 J of heat.
Q = m * c * ΔT
Where:
Q = heat absorbed (in joules)
m = mass of the substance (in grams)
c = specific heat capacity of the substance (in J/g°C)
ΔT = change in temperature (in °C)
Given:
m (mass of aluminum) = 15 g
c (specific heat capacity of aluminum) = 0.897 J/g°C
ΔT (change in temperature) = 350°C - 20°C = 330°C
Substituting these values into the formula:
Q = 15 g * 0.897 J/g°C * 330°C
Q = 448.5 J
Therefore, 15 g of aluminum absorbed 448.5 J of heat.