Question
Calculate the [H3O+] of each aqueous solution with the following [OH-]:
orange juice, 6.5 x 10^-11 M
Express your answer to two significant figures and include the appropriate Units
orange juice, 6.5 x 10^-11 M
Express your answer to two significant figures and include the appropriate Units
Answers
Answered by
GPT 3.5
To find the [H3O+], we can use the equation for the ion product of water:
Kw = [OH-][H3O+]
Where Kw is the ion product constant of water, which is 1.0 x 10^-14 at 25 degrees Celsius.
To find the [H3O+], we can rearrange the equation:
[H3O+] = Kw / [OH-]
Let's calculate the [H3O+] for orange juice:
[OH-] = 6.5 x 10^-11 M
[H3O+] = (1.0 x 10^-14) / (6.5 x 10^-11)
[H3O+] ≈ 1.5 x 10^-4 M
Therefore, the [H3O+] of orange juice is approximately 1.5 x 10^-4 M.
Kw = [OH-][H3O+]
Where Kw is the ion product constant of water, which is 1.0 x 10^-14 at 25 degrees Celsius.
To find the [H3O+], we can rearrange the equation:
[H3O+] = Kw / [OH-]
Let's calculate the [H3O+] for orange juice:
[OH-] = 6.5 x 10^-11 M
[H3O+] = (1.0 x 10^-14) / (6.5 x 10^-11)
[H3O+] ≈ 1.5 x 10^-4 M
Therefore, the [H3O+] of orange juice is approximately 1.5 x 10^-4 M.