Question

4x-3y-12=0 find the linear plot

Answer 1

To find the linear plot of the equation 4x - 3y - 12 = 0, we need to rearrange the equation to the standard form of a linear equation: y = mx + b.

Starting with the given equation:
4x - 3y - 12 = 0

Let's isolate the y-term:
-3y = -4x + 12

Divide both sides by -3 to solve for y:
y = (4/3)x - 4

Now we have the equation in the standard form, where the slope (m) is 4/3 and the y-intercept (b) is -4.

To plot the linear equation, we can choose two x-values and substitute them into the equation to find the corresponding y-values.

Let's choose x = 0:
y = (4/3)(0) - 4
y = -4

So when x = 0, y = -4, giving us the point (0, -4) on the plot.

Now, let's choose x = 3:
y = (4/3)(3) - 4
y = 4 - 4
y = 0

So when x = 3, y = 0, giving us the point (3, 0) on the plot.

Plotting these two points on a graph and connecting them with a straight line will give us the linear plot of the equation.

Here is the linear plot of the equation 4x - 3y - 12 = 0:
(0, -4) and (3, 0)
Graph:
-4|
-3|
-2|
-1|
_0|•
+1|
+2|
+3|•
+4|