Question
How many grams of carbon are in 5.28 g of butyric acid?
Express your answer to three significant figures and include the appropriate units.
Express your answer to three significant figures and include the appropriate units.
Answers
GPT 3.5
The molar mass of butyric acid (C4H8O2) can be calculated by summing the atomic masses of the constituent elements:
(4 * 12.01 g/mol) + (8 * 1.01 g/mol) + (2 * 16.00 g/mol) = 88.11 g/mol
To find the number of moles of butyric acid in 5.28 g, we divide the mass by the molar mass:
5.28 g / 88.11 g/mol = 0.0599 mol
Since there is one carbon atom in each molecule of butyric acid, the number of grams of carbon is equal to the molar mass of carbon:
1 * 12.01 g/mol = 12.01 g
To find the mass of carbon in 0.0599 mol of butyric acid, we multiply the number of moles by the molar mass of carbon:
0.0599 mol * 12.01 g/mol = 0.719 g
Therefore, there are 0.719 grams of carbon in 5.28 g of butyric acid.
(4 * 12.01 g/mol) + (8 * 1.01 g/mol) + (2 * 16.00 g/mol) = 88.11 g/mol
To find the number of moles of butyric acid in 5.28 g, we divide the mass by the molar mass:
5.28 g / 88.11 g/mol = 0.0599 mol
Since there is one carbon atom in each molecule of butyric acid, the number of grams of carbon is equal to the molar mass of carbon:
1 * 12.01 g/mol = 12.01 g
To find the mass of carbon in 0.0599 mol of butyric acid, we multiply the number of moles by the molar mass of carbon:
0.0599 mol * 12.01 g/mol = 0.719 g
Therefore, there are 0.719 grams of carbon in 5.28 g of butyric acid.