To determine the amount of NH3 produced, we need to use stoichiometry and the molar ratios given in the balanced equation.
First, we need to convert the given mass of H2 to moles. The molar mass of H2 is 2.02 g/mol.
Moles of H2 = 3.32 g H2 / 2.02 g/mol H2 = 1.646 moles H2
Next, we can use the stoichiometry of the balanced equation to determine the moles of NH3 produced. According to the balanced equation, 3 moles of H2 react to produce 2 moles of NH3.
Moles of NH3 = 1.646 moles H2 × (2 moles NH3 / 3 moles H2) = 1.097 moles NH3
Finally, we can convert the moles of NH3 to grams using the molar mass of NH3, which is 17.03 g/mol.
Grams of NH3 = 1.097 moles NH3 × 17.03 g/mol NH3 = 18.68 g NH3
Therefore, 3.32 g of H2 can produce 18.68 g of NH3.
Nitrogen gas reacts with hydrogen gas to produce ammonia via the following reaction:
N2 (g) + 3H2(g) →2NH3 (g)
• Part A
If you have 3.32 g of H2, how many grams of NH3 can be produced?
Express your answer with the appropriate units.
1 answer