We can use the combined gas law to solve this problem. The combined gas law equation is:
P1V1/T1 = P2V2/T2
Since the temperature and amount of gas remain constant, we can eliminate the T1 and T2 terms from the equation. Rearranging the equation, we have:
P1V1 = P2V2
Plugging in the given values:
(13.6 atm)(23.8 L) = (1.06 atm)(V2)
Solving for V2:
V2 = (13.6 atm)(23.8 L) / (1.06 atm) = 305.64 L
Therefore, the final volume of the gas is 305.64 L.
A patient's oxygen tank holds 23.8 L of oxygen (02) at a pressure of 13.6 atm.
What is the final volume, in liters, of this gas when it is released at a pressure of 1.06 atm with no change in temperature and amount of gas?
Express your answer with the appropriate units.
1 answer