Question
A patient's oxygen tank holds 23.8 L of oxygen (02) at a pressure of 13.6 atm.
What is the final volume, in liters, of this gas when it is released at a pressure of 1.06 atm with no change in temperature and amount of gas?
Express your answer with the appropriate units.
What is the final volume, in liters, of this gas when it is released at a pressure of 1.06 atm with no change in temperature and amount of gas?
Express your answer with the appropriate units.
Answers
GPT 3.5
We can use the combined gas law to solve this problem. The combined gas law equation is:
P1V1/T1 = P2V2/T2
Since the temperature and amount of gas remain constant, we can eliminate the T1 and T2 terms from the equation. Rearranging the equation, we have:
P1V1 = P2V2
Plugging in the given values:
(13.6 atm)(23.8 L) = (1.06 atm)(V2)
Solving for V2:
V2 = (13.6 atm)(23.8 L) / (1.06 atm) = 305.64 L
Therefore, the final volume of the gas is 305.64 L.
P1V1/T1 = P2V2/T2
Since the temperature and amount of gas remain constant, we can eliminate the T1 and T2 terms from the equation. Rearranging the equation, we have:
P1V1 = P2V2
Plugging in the given values:
(13.6 atm)(23.8 L) = (1.06 atm)(V2)
Solving for V2:
V2 = (13.6 atm)(23.8 L) / (1.06 atm) = 305.64 L
Therefore, the final volume of the gas is 305.64 L.