Asked by Jamie
A ball is thrown vertically upward with a speed of 1.53 m/s from a point 4.21 m above the ground. Calculate the time in which the ball will reach the ground.
{Distance Above Ground} = D = (4.21) + (1.53)*t + (1/2)*(-9.8)*t^2
{D = 0} ----> {Time To Reach Ground} = 1.096 sec
Is this right?
{Distance Above Ground} = D = (4.21) + (1.53)*t + (1/2)*(-9.8)*t^2
{D = 0} ----> {Time To Reach Ground} = 1.096 sec
Is this right?
Answers
Answered by
bobpursley
I didn't check your math, but the equation is right. Do this: put the answer in the google search window to calculate it .
(4.21) + (1.53)*1.096 + (1/2)*(-9.8)*(1.096)^2
(4.21) + (1.53)*1.096 + (1/2)*(-9.8)*(1.096)^2
Answered by
DaBaby
Listen to my song BOP hit up da likes
Answered by
Pete
What is the equation for this without the numbers slotted in
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.