determine how many mL's of a monohydroxic base with a pH of 9 is needed to neutralize 50 mL of a monoprotic acid with a pH of 2. I do not understand what to do. can someone please help?

Answer 1

the H+ must equal the OH-

H+=10^-9=> OH=10^-5
H+=10^-2

50*10^-2=V*10-5
V=50ml*10^3 or 50 liters