Asked by jackie
determine how many mL's of a monohydroxic base with a pH of 9 is needed to neutralize 50 mL of a monoprotic acid with a pH of 2. I do not understand what to do. can someone please help?
Answers
Answered by
bobpursley
the H+ must equal the OH-
H+=10^-9=> OH=10^-5
H+=10^-2
50*10^-2=V*10-5
V=50ml*10^3 or 50 liters
H+=10^-9=> OH=10^-5
H+=10^-2
50*10^-2=V*10-5
V=50ml*10^3 or 50 liters
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