Asked by Doris
Raising rabbits. Before Roland sold two female rabbits,
half of his rabbits were female. After the sale, only onethird
of his rabbits were female. If x represents his original
number of rabbits, then
1
2
x 2
1
3
(x 2).
Solve this equation to find the number of rabbits that he
had before the sale.
half of his rabbits were female. After the sale, only onethird
of his rabbits were female. If x represents his original
number of rabbits, then
1
2
x 2
1
3
(x 2).
Solve this equation to find the number of rabbits that he
had before the sale.
Answers
Answered by
DrBob222
I can't read your post.
If x = original number of rabbits, then
(1/2) x = # female rabbits and
(1/2) x = # male rabbits.
Then if Roland sold 2 female rabbits, the number female rabbits now is (1/2)x -2 and that = (1/3)x
So (1/2)x -2 = (1/3)x. Solve for x.
I obtained 12 for the original number of rabbits. Check my thinking. Check my work.
If x = original number of rabbits, then
(1/2) x = # female rabbits and
(1/2) x = # male rabbits.
Then if Roland sold 2 female rabbits, the number female rabbits now is (1/2)x -2 and that = (1/3)x
So (1/2)x -2 = (1/3)x. Solve for x.
I obtained 12 for the original number of rabbits. Check my thinking. Check my work.
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