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Original Question
What is the irrational cube root ^3√48 rewritten as a product of an integer and another irrational cube root?Asked by cumshots
What is the irrational cube root 3√40
rewritten as a product of an integer and another irrational cube root?
rewritten as a product of an integer and another irrational cube root?
Answers
Answered by
cumshots
the options are
A. 2 3√5
B. 2 3√10
C.-2 3√5
D. 8 3√5
A. 2 3√5
B. 2 3√10
C.-2 3√5
D. 8 3√5
Answered by
cumshots
correct
Awnsers are:
D. 4√3
A. 2√7
A. 2 3√6
D. -2 3√3
A. 2 3√5
All 100% for connexus
Awnsers are:
D. 4√3
A. 2√7
A. 2 3√6
D. -2 3√3
A. 2 3√5
All 100% for connexus
Answered by
thankss <3
cumsh0ts... is correct 100% thank u sm.!
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