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A membership at Gym A costs $50 for 5 months. A membership at Gym B down the street costs $40 for 3 months. You write two equat...Question
A membership at Gym A cost $50 for 5 months. A membership at Gym B down the street costs $40 for 3 months. You write two equations in the form of y=kx to try and figure out which membership would be cheaper for a year. What is the value of k for the cheaper membership?
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Answered by
Plz help me
Y’all the answer is 10
Answered by
Plz help me
I took the quick check so I’m correct
Answered by
GPT 3.5
Let's assume that x represents the number of months and y represents the cost of the membership.
For Gym A:
The membership at Gym A costs $50 for 5 months.
Therefore, the equation for Gym A is y = 50/5 * x, which simplifies to y = 10x.
For Gym B:
The membership at Gym B costs $40 for 3 months.
Therefore, the equation for Gym B is y = 40/3 * x, which simplifies to y = (40/3)x.
To determine which membership is cheaper for a year (12 months), we can compare the costs for x = 12.
For Gym A:
y = 10x
y = 10 * 12
y = 120
For Gym B:
y = (40/3)x
y = (40/3) * 12
y = 160
Comparing the costs, we can see that Gym A is cheaper for a year, with a cost of $120.
The value of k for the cheaper membership (Gym A) is therefore 10.
For Gym A:
The membership at Gym A costs $50 for 5 months.
Therefore, the equation for Gym A is y = 50/5 * x, which simplifies to y = 10x.
For Gym B:
The membership at Gym B costs $40 for 3 months.
Therefore, the equation for Gym B is y = 40/3 * x, which simplifies to y = (40/3)x.
To determine which membership is cheaper for a year (12 months), we can compare the costs for x = 12.
For Gym A:
y = 10x
y = 10 * 12
y = 120
For Gym B:
y = (40/3)x
y = (40/3) * 12
y = 160
Comparing the costs, we can see that Gym A is cheaper for a year, with a cost of $120.
The value of k for the cheaper membership (Gym A) is therefore 10.
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