Let x be the number of $10 notes Ravi initially had.
So the number of $50 notes is 80 - x.
After using 1/2 of his $10 notes, Ravi had x/2 $10 notes left.
After depositing 8 pieces of $50 notes into the bank, Ravi had 80 - x - 8 = 72 - x $50 notes left.
According to the problem, the number of $50 notes he had left is 2/5 of the number of $10 notes he had left.
So, 72 - x = (2/5)(x/2).
Multiplying both sides of the equation by 10 to remove the fraction, we get 720 - 10x = 4x.
Adding 10x to both sides of the equation, we get 720 = 14x.
Dividing both sides of the equation by 14, we get x = 720/14 = 51.43.
Since we can't have a fraction of a note, we take the nearest whole number, which is x = 51.
Thus, the initial number of $10 notes Ravi had was 51, and the initial number of $50 notes was 80 - 51 = 29.
So the total value of the 80 pieces of notes that he had at first was 51 * $10 + 29 * $50 = $510 + $1450 = $<<51*10+29*50=2000>>2000. Answer: \boxed{2000}.
Ravi had a total of 80 pieces of $10 notes and $50 notes. He used 1/2 of his $10 notes and deposit 8 pieces of $50 into the bank. After which, the number of $50 notes he had became 2/5 of the number of $10 notes. Find the total value of the
80 pieces of notes that he had at first
1 answer