To find the equation of the line perpendicular to y = -5/3x + 11 1/3, we need to determine the negative reciprocal of the slope of the given line.
The given line has a slope of -5/3. The negative reciprocal is 3/5.
Now, we will use the point-slope form of a linear equation to find the equation of the line containing point P(-2, 3) and with a slope of 3/5.
The point-slope form is given by: y - y1 = m(x - x1),
where (x1, y1) is a point on the line and m is the slope.
Plugging in the values, we have:
y - 3 = 3/5(x - (-2))
y - 3 = 3/5(x + 2)
Simplifying the equation, we get:
y - 3 = 3/5x + 6/5
y = 3/5x + 6/5 + 3
y = 3/5x + 6/5 + 15/5
Combining the fractions, we have:
y = 3/5x + 21/5
Therefore, the equation for the line perpendicular to y = -5/3x + 11 1/3 and containing P(-2, 3) is:
y = 3/5x + 21/5.
Which is the equation for the line perpendicular to y= -5/3x+11 1/3 and containing P(-2, 3)?
y-2=-3/5(x-3)
y=-5/3x+4 1/3
y-3/5x+4 1/5
y=3/5x+4 1/5
5 answers
Two lines are perpendicular when (1 point) Responses
the product of their slopes is -1.
the product of their slopes is greater than 0.
they have the same slope.
their slopes are undefined.
the product of their slopes is -1.
the product of their slopes is greater than 0.
they have the same slope.
their slopes are undefined.
The correct answer is:
the product of their slopes is -1.
the product of their slopes is -1.
thank you for the help, everything was 100% correct
You're welcome! I'm glad I could assist you. If you have any more questions, feel free to ask!
1 answer