The equation for the total cars and trucks for Dealership A is x + y = 225, where x represents the number of cars sold and y represents the number of trucks sold.
The equation for the total cars and trucks for Dealership B is 2x + 1/2y = 300.
Since Dealership B sold twice as many cars as Dealership A, the value of x for Dealership B would be twice the value of x for Dealership A. So, x = 2 * 125 = 250.
Given that Dealership B sold half as many trucks as Dealership A, the value of y for Dealership B would be half the value of y for Dealership A. So, y = 1/2 * 50 = 25.
Therefore, Dealership A sold 125 cars and Dealership B sold 25 trucks.
A company owns two dealerships, both of which sell cars and trucks. Dealership A sells a total of 225 cars and trucks. Dealership B sells twice as many cars and half as many trucks as the Dealership A, and sells a total of 300 cars and trucks. (4 points) a) An equation for the total cars and trucks for Dealership A: x + y = 225 b) An equation for the total cars and trucks for Dealership B: 2x + 1/2y = 300 c) How many cars did Dealership A sell? 125 d) Given the fact that Dealership B sold half as many trucks as Dealership A, how many trucks did Dealership B sell? 50
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are you sure
Apologies for the confusion. Let's double-check the calculations and solve the problem correctly.
a) We are given that Dealership A sold a total of 225 cars and trucks. Therefore, we can set up the equation:
x + y = 225
b) Dealership B sold twice as many cars as Dealership A and half as many trucks. So, we have:
2x + (1/2)y = 300
c) To find the number of cars sold by Dealership A, we can use the equation from part a:
x + y = 225
Since we are interested in the number of cars sold by Dealership A, we set y (number of trucks sold by Dealership A) to zero. The equation becomes:
x + 0 = 225
x = 225
Therefore, Dealership A sold 225 cars.
d) Given that Dealership B sold half as many trucks as Dealership A, we can substitute the value of y (number of trucks sold by Dealership A) into the equation from part b:
2x + (1/2)y = 300
Since Dealership B sold half as many trucks as Dealership A, y is half of the number of trucks sold by Dealership A. The equation becomes:
2x + (1/2)(2y) = 300
2x + y = 300
To find the value of y (number of trucks sold by Dealership B), we need to solve this equation. From part c, we know that x = 225. Substituting this value into the equation:
2(225) + y = 300
450 + y = 300
y = 300 - 450
y = -150
Therefore, Dealership B sold -150 trucks. However, this result is not possible in a real scenario. There seems to be a mistake or inconsistency in the given information.
I apologize for any confusion caused. Please double-check the problem statement or provide additional information if needed.
a) We are given that Dealership A sold a total of 225 cars and trucks. Therefore, we can set up the equation:
x + y = 225
b) Dealership B sold twice as many cars as Dealership A and half as many trucks. So, we have:
2x + (1/2)y = 300
c) To find the number of cars sold by Dealership A, we can use the equation from part a:
x + y = 225
Since we are interested in the number of cars sold by Dealership A, we set y (number of trucks sold by Dealership A) to zero. The equation becomes:
x + 0 = 225
x = 225
Therefore, Dealership A sold 225 cars.
d) Given that Dealership B sold half as many trucks as Dealership A, we can substitute the value of y (number of trucks sold by Dealership A) into the equation from part b:
2x + (1/2)y = 300
Since Dealership B sold half as many trucks as Dealership A, y is half of the number of trucks sold by Dealership A. The equation becomes:
2x + (1/2)(2y) = 300
2x + y = 300
To find the value of y (number of trucks sold by Dealership B), we need to solve this equation. From part c, we know that x = 225. Substituting this value into the equation:
2(225) + y = 300
450 + y = 300
y = 300 - 450
y = -150
Therefore, Dealership B sold -150 trucks. However, this result is not possible in a real scenario. There seems to be a mistake or inconsistency in the given information.
I apologize for any confusion caused. Please double-check the problem statement or provide additional information if needed.
Dealership a sold 125 cars and 100 trucks if dealership b sold twice as many cars than dealership a and half as many trucks than dealership a how many cars and trucks did dealer ship b sold
Given that Dealership A sold 125 cars and 100 trucks, we know that x (the number of cars sold by Dealership A) is 125 and y (the number of trucks sold by Dealership A) is 100.
We are also told that Dealership B sold twice as many cars as Dealership A and half as many trucks. Therefore, the number of cars sold by Dealership B is 2 times the number of cars sold by Dealership A, which is 2 * 125 = 250.
The number of trucks sold by Dealership B is half the number of trucks sold by Dealership A, which is 1/2 * 100 = 50.
Therefore, Dealership B sold 250 cars and 50 trucks.
We are also told that Dealership B sold twice as many cars as Dealership A and half as many trucks. Therefore, the number of cars sold by Dealership B is 2 times the number of cars sold by Dealership A, which is 2 * 125 = 250.
The number of trucks sold by Dealership B is half the number of trucks sold by Dealership A, which is 1/2 * 100 = 50.
Therefore, Dealership B sold 250 cars and 50 trucks.
correct if anyone asks you the question at the top give them these answers A company owns two dealerships, both of which sell cars and trucks. Dealership A sells a total of 225 cars and trucks. Dealership B sells twice as many cars and half as many trucks as the Dealership A, and sells a total of 300 cars and trucks. (4 points) a) An equation for the total cars and trucks for Dealership A: x + y = 225 b) An equation for the total cars and trucks for Dealership B: 2x + 1/2y = 300 c) How many cars did Dealership A sell? 125 d) Given the fact that Dealership B sold half as many trucks as Dealership A, how many trucks did Dealership B sell? 50
a) An equation for the total cars and trucks for Dealership A: x + y = 225
b) An equation for the total cars and trucks for Dealership B: 2x + 1/2y = 300
c) Dealership A sold 125 cars.
d) Dealership B sold 50 trucks.
b) An equation for the total cars and trucks for Dealership B: 2x + 1/2y = 300
c) Dealership A sold 125 cars.
d) Dealership B sold 50 trucks.
1 answer