How would you locate the solution of the two linear graphs on the coordinate plane? - The solution can be located at the point (3,9) on the coordinate plane.
How could you get exactly two or three solutions to this linear system? - By having two or three intersecting lines on the coordinate plane.
The solution to this system could possibly have this meaning. - The meaning could be that after 3 weeks, the height is 9 feet.
The solution to a system of two linear equations is x = 3 weeks; y = 9 feet Match the description with the correct statement. (3 points) Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse. How would you locate the solution of the two linear graphs on the coordinate plane? How could you get exactly two or three solutions to this linear system? The solution to this system could possibly have this meaning.
21 answers
How could you check to see if the point (5, 6) is the solution to the Linear System of equations?(1 point) Responses Substitute 6 in for x and 5 in for y in both of the equations to see if both equations are true. Substitute 6 in for x and 5 in for y in both of the equations to see if both equations are true. Substitute 6 in for x and 5 in for y in one of the equations to see if the equation is true. Substitute 6 in for x and 5 in for y in one of the equations to see if the equation is true. Substitute 5 in for x and 6 in for y in both of the equations to see if both equations are true. Substitute 5 in for x and 6 in for y in both of the equations to see if both equations are true. Substitute 5 in for x and 6 in for y in one of the equations to see if the equation is true.
To check if the point (5, 6) is the solution to the linear system of equations, you would substitute 5 in for x and 6 in for y in both of the equations to see if both equations are true.
You are running a concession stand at a baseball game. You are selling pizza slices and sodas. Each pizza slice sells for $3.50 and each soda sells for $1.50. At the end of the night, you made a total of $800. You sold a total of 344 pizza slices and sodas combined. You must report the number of pizza slices sold and the number of sodas sold. What equations did you use to solve this, where P = the number of pizza slices sold and S = the number of sodas sold? (1 point) Responses 3.50S + 1.50P = 800 and P + S = 344 3.50S + 1.50P = 800 and P + S = 344 3.50P + 1.50S = 800 and P + S = 344 3.50P + 1.50S = 800 and P + S = 344 3.50S + 1.50P = 344 and P + S = 800 3.50S + 1.50P = 344 and P + S = 800 3.50P + S = 800 and P + 1.50S = 344 3.50P + S = 800 and P + 1.50S = 344
The equations used to solve this would be:
3.50P + 1.50S = 800 (equation representing the total amount made)
P + S = 344 (equation representing the total number of pizza slices and sodas sold)
3.50P + 1.50S = 800 (equation representing the total amount made)
P + S = 344 (equation representing the total number of pizza slices and sodas sold)
Check all that apply. Select the statement(s) that correctly describes the solution to this system of equations: 8x−2y=−4 4x−y=−2 (2 points) Responses Solve this system by elimination since it is already in standard form and lined up nicely. Solve this system by elimination since it is already in standard form and lined up nicely. There is exactly one solution to this system of linear equations and it is (2, 0). There is exactly one solution to this system of linear equations and it is (2, 0). There are infinite solutions to this system of linear equations. There are infinite solutions to this system of linear equations. These lines are parallel, so there is no solution to this system of linear equations. These lines are parallel, so there is no solution to this system of linear equations. There is exactly one solution to this system of linear equations and it is (0, -2). There is exactly one solution to this system of linear equations and it is (0, -2). Solve this system by substitution since one of the variables is defined by the other without having to do any math.
The statement "There is exactly one solution to this system of linear equations and it is (2, 0)" is correct.
The statement "These lines are parallel, so there is no solution to this system of linear equations" is correct.
The statement "There are infinite solutions to this system of linear equations" is incorrect.
The statement "Solve this system by elimination since it is already in standard form and lined up nicely" is incorrect.
The statement "Solve this system by substitution since one of the variables is defined by the other without having to do any math" is incorrect.
The statement "These lines are parallel, so there is no solution to this system of linear equations" is correct.
The statement "There are infinite solutions to this system of linear equations" is incorrect.
The statement "Solve this system by elimination since it is already in standard form and lined up nicely" is incorrect.
The statement "Solve this system by substitution since one of the variables is defined by the other without having to do any math" is incorrect.
im bought some potted plants: Petunias cost $11 per pot and Begonias cost $15 per pot. Jim bought 19 potted plants in all and spent a total of $225 on the plants. Which would be a correct statement? (1 point) Responses Jim bought 15 begonias. Jim bought 15 begonias. Jim bought 15 petunias. Jim bought 15 petunias. Jim bought 4 petunias. Jim bought 4 petunias. Jim bought 18 begonias.
Jim bought 15 petunias.
9 of 169 of 16 Items Question Solve the system of equations graphically. You can use your graphing calculator!
y=−2x−1
3x − y =−7
y=−2x−1
3x − y =−7
To solve the system of equations graphically, you can plot the graphs of the two equations on a coordinate plane and find the point of intersection.
For the equation y = -2x - 1, plot points on the graph using various x-values and calculate the corresponding y-values. This will give you a straight line on the graph.
For the equation 3x - y = -7, rearrange it to y = 3x + 7 and plot points on the graph using different x-values and calculate the corresponding y-values. This will also give you a straight line on the graph.
Once you have plotted both lines, find the point where the two lines intersect. The coordinates of this point will be the solution to the system of equations.
You can use a graphing calculator to plot the lines and find the point of intersection, which will give you the solution to the system of equations.
For the equation y = -2x - 1, plot points on the graph using various x-values and calculate the corresponding y-values. This will give you a straight line on the graph.
For the equation 3x - y = -7, rearrange it to y = 3x + 7 and plot points on the graph using different x-values and calculate the corresponding y-values. This will also give you a straight line on the graph.
Once you have plotted both lines, find the point where the two lines intersect. The coordinates of this point will be the solution to the system of equations.
You can use a graphing calculator to plot the lines and find the point of intersection, which will give you the solution to the system of equations.
whats the solution
To find the solution to the system of equations, we can solve them simultaneously.
The given equations are:
1) y = -2x - 1
2) 3x - y = -7
We can substitute the value of y from equation 1 into equation 2:
3x - (-2x - 1) = -7
3x + 2x + 1 = -7
5x + 1 = -7
5x = -8
x = -8/5 or -1.6
Substituting this value of x into equation 1:
y = -2(-1.6) - 1
y = 3.2 - 1
y = 2.2
Therefore, the solution to the system of equations is x = -1.6 and y = 2.2.
The given equations are:
1) y = -2x - 1
2) 3x - y = -7
We can substitute the value of y from equation 1 into equation 2:
3x - (-2x - 1) = -7
3x + 2x + 1 = -7
5x + 1 = -7
5x = -8
x = -8/5 or -1.6
Substituting this value of x into equation 1:
y = -2(-1.6) - 1
y = 3.2 - 1
y = 2.2
Therefore, the solution to the system of equations is x = -1.6 and y = 2.2.
1. Choose the best method to solve by looking at the way the equations are set up for you: Response area 2. Using the best method, how could you get the x variables to cancel out? Response area 3. After you complete step 2, what would your top equation be? Response area 4. Line them up and add the equations together to get this equation. Response area 5. Solve for y. Response area 6. Solve for x. Response area Choose a method Operation to get the x variables to cancel Simplified top equation After adding the equations Solve for x and y Skip to navigation
1. Choose the best method to solve by looking at the way the equations are set up for you:
- It appears that the best method to solve this system of equations is the method of elimination.
2. Using the best method, how could you get the x variables to cancel out?
- To cancel out the x variables, you can multiply the first equation by 3, and the second equation by 2. This will create coefficients that will allow you to add the two equations together and eliminate the x variable.
3. After you complete step 2, what would your top equation be?
- After multiplying the first equation by 3, and the second equation by 2, the top equation would become:
6x - 3y = -3
4. Line them up and add the equations together to get this equation.
- After lining up the two equations and adding them together, you would get:
6x - 3y + 2x - y = -3 -7
8x - 4y = -10
5. Solve for y.
- To solve for y, we need to isolate the variable. So, continuing from the previous equation:
8x - 4y = -10
-4y = -10 - 8x
y = (10 + 8x)/4
y = (5 + 4x)/2
y = 2 + 2x
6. Solve for x.
- Currently, we have an expression for y in terms of x, but we don't have a specific value for x. It seems we can't determine an exact value for x from the given equations.
- It appears that the best method to solve this system of equations is the method of elimination.
2. Using the best method, how could you get the x variables to cancel out?
- To cancel out the x variables, you can multiply the first equation by 3, and the second equation by 2. This will create coefficients that will allow you to add the two equations together and eliminate the x variable.
3. After you complete step 2, what would your top equation be?
- After multiplying the first equation by 3, and the second equation by 2, the top equation would become:
6x - 3y = -3
4. Line them up and add the equations together to get this equation.
- After lining up the two equations and adding them together, you would get:
6x - 3y + 2x - y = -3 -7
8x - 4y = -10
5. Solve for y.
- To solve for y, we need to isolate the variable. So, continuing from the previous equation:
8x - 4y = -10
-4y = -10 - 8x
y = (10 + 8x)/4
y = (5 + 4x)/2
y = 2 + 2x
6. Solve for x.
- Currently, we have an expression for y in terms of x, but we don't have a specific value for x. It seems we can't determine an exact value for x from the given equations.
1. Choose the best method to solve by looking at the way the equations are set up for you: Response area 2. Using the best method, how could you get the x variables to cancel out? Response area 3. After you complete step 2, what would your top equation be? Response area 4. Line them up and add the equations together to get this equation. Response area 5. Solve for y. Response area 6. Solve for x. Response area Choose a method Operation to get the x variables to cancel Simplified top equation After adding the equations Solve for x and y Skip to navigation
on 2. the options are divide the bottom equation by 2
multiply the bottom equation by x 2
multiply the top equation by x -2
divide the top equation by 4
on 2. the options are divide the bottom equation by 2
multiply the bottom equation by x 2
multiply the top equation by x -2
divide the top equation by 4
1. Choose the best method to solve by looking at the way the equations are set up for you: Elimination method
2. Using the best method, how could you get the x variables to cancel out? Multiply the top equation by 2 and multiply the bottom equation by -2
3. After you complete step 2, what would your top equation be? -4x + 2y = 2
4. Line them up and add the equations together to get this equation. -4x + 2y + 4x - 2y = 2 -7
5. Solve for y. 0 = -5
6. Solve for x. Since there is no value of y that satisfies the given equations, there is no solution for x either.
2. Using the best method, how could you get the x variables to cancel out? Multiply the top equation by 2 and multiply the bottom equation by -2
3. After you complete step 2, what would your top equation be? -4x + 2y = 2
4. Line them up and add the equations together to get this equation. -4x + 2y + 4x - 2y = 2 -7
5. Solve for y. 0 = -5
6. Solve for x. Since there is no value of y that satisfies the given equations, there is no solution for x either.
wrong
I apologize for the incorrect response. Let's go through the correct steps:
1. Choose the best method to solve by looking at the way the equations are set up for you: The best method is still elimination method.
2. Using the best method, how could you get the x variables to cancel out? Multiply the top equation by 2 and the bottom equation by 3. This will make the coefficients of x in both equations have opposite signs, allowing them to cancel out when added together.
3. After you complete step 2, what would your top equation be? The top equation would be 6x - 2y = -2.
4. Line them up and add the equations together to get this equation. Adding the equations together:
(6x - 2y) + (6x - y) = (-2) + (-7)
Simplifying:
12x - 3y = -9
5. Solve for y. To solve for y, we isolate y in the equation:
12x - 3y = -9
-3y = -9 - 12x
Divide by -3:
y = 3 + 4x
6. Solve for x. We already have y in terms of x, but we cannot solve for a specific x value with the given equations.
1. Choose the best method to solve by looking at the way the equations are set up for you: The best method is still elimination method.
2. Using the best method, how could you get the x variables to cancel out? Multiply the top equation by 2 and the bottom equation by 3. This will make the coefficients of x in both equations have opposite signs, allowing them to cancel out when added together.
3. After you complete step 2, what would your top equation be? The top equation would be 6x - 2y = -2.
4. Line them up and add the equations together to get this equation. Adding the equations together:
(6x - 2y) + (6x - y) = (-2) + (-7)
Simplifying:
12x - 3y = -9
5. Solve for y. To solve for y, we isolate y in the equation:
12x - 3y = -9
-3y = -9 - 12x
Divide by -3:
y = 3 + 4x
6. Solve for x. We already have y in terms of x, but we cannot solve for a specific x value with the given equations.
u got all wrong
I apologize for the mistakes. Let's go through the correct steps:
1. Choose the best method to solve by looking at the way the equations are set up for you: The best method is still elimination method.
2. Using the best method, how could you get the x variables to cancel out? Multiply the top equation by 3 and the bottom equation by 2. This will make the coefficients of x in both equations have the same value, allowing them to cancel out when subtracted.
3. After you complete step 2, what would your top equation be? The top equation would be 6x - 3y = -3.
4. Line them up and add the equations together to get this equation. Subtracting the equations:
(6x - 3y) - (6x - y) = (-3) - (-7)
Simplifying:
-2y = 4
Divide by -2:
y = -2
5. Solve for x. Now we have the value of y, we can substitute it into either of the original equations. Let's use the first equation:
y = -2
-2x - 1 = -2
-2x = -2 + 1
-2x = -1
Divide by -2:
x = 1/2
So, the solution to the system of equations is x = 1/2 and y = -2.
1. Choose the best method to solve by looking at the way the equations are set up for you: The best method is still elimination method.
2. Using the best method, how could you get the x variables to cancel out? Multiply the top equation by 3 and the bottom equation by 2. This will make the coefficients of x in both equations have the same value, allowing them to cancel out when subtracted.
3. After you complete step 2, what would your top equation be? The top equation would be 6x - 3y = -3.
4. Line them up and add the equations together to get this equation. Subtracting the equations:
(6x - 3y) - (6x - y) = (-3) - (-7)
Simplifying:
-2y = 4
Divide by -2:
y = -2
5. Solve for x. Now we have the value of y, we can substitute it into either of the original equations. Let's use the first equation:
y = -2
-2x - 1 = -2
-2x = -2 + 1
-2x = -1
Divide by -2:
x = 1/2
So, the solution to the system of equations is x = 1/2 and y = -2.
1 answer