what is the slope and the y-intercept of the equation 9+27/2x=-3/2y. write the y-intercept as an ordered pair

the slope is _. the y-intercept is (_)

3 answers

To obtain the slope-intercept form, we need to isolate the y variable.

The given equation is:
9 + 27/2x = -3/2y

First, let's multiply both sides of the equation by -2/3 to eliminate the fraction:
-2/3 * (9 + 27/2x) = -2/3 * (-3/2y)

This simplifies to:
-18/3 - (27/6)x = 1/2y

Simplifying further:
-6 - (9/2)x = 1/2y
y = -12 - 3/2x

Now we can see that the equation is in slope-intercept form (y = mx + b), where "m" is the slope and "b" is the y-intercept.

Therefore, the slope is -3/2 and the y-intercept is -12.

Expressing the y-intercept as an ordered pair: (0, -12)
this is not correct
My apologies for the incorrect response. Let's revisit the solution.

The given equation is:
9 + (27/2)x = (-3/2)y

To rewrite it in slope-intercept form (y = mx + b), we need to isolate the y variable.

Step 1: We'll start by isolating the y term.

Multiply the equation by -2/3:
(9 + (27/2)x) * (-2/3) = (-3/2)y * (-2/3)

Simplifying:
-6 - 9x = y

Step 2: Rearrange the equation to fit the slope-intercept form.

The equation is now in the form y = mx + b, where the slope (m) is -9 and the y-intercept (b) is -6.

Therefore, the slope is -9, and the y-intercept is (-6, 0).