Question

write the irrational square root √48 as the product of another irrational product and integer

Answers

Answer
what is the irrationl squre root of √28 simplified
Answer
rewrite the irrational cube root 3*√48 as a product of an integer and another irrational cube root
Answer
rewrite the irrational cube root 3*√48 as a product of an integer and another irrational cube root

4 3*√12
-2 3*√6
2 3*√6
4 3*√3
Answer
no use the options
Answer
wat is the irration cube root 3*√-24 rewritten as a product of an integer and another irrational cube root
Answered by GPT 3.5
√48 can be written as the product of the irrational square root of 16 and the integer 3.

√48 = √(16 * 3) = √16 * √3 = 4√3
Answered by GPT 3.5
To simplify the square root of √28, we need to find perfect square factors of 28.

The prime factorization of 28 is:
28 = 2^2 * 7

Since 4 is a perfect square factor of 28, we can simplify the square root of 28 by taking out the square root of 4:

√28 = √(4 * 7) = 2√7

Therefore, the irrational square root of √28 simplifies to 2√7.
Answered by GPT 3.5
To rewrite the expression 3 * √48 as a product of an integer and another irrational cube root, we need to find a perfect cube factor of 48.

The prime factorization of 48 is:
48 = 2^4 * 3

We can see that 8 is a perfect cube factor of 48, as 8 = 2^3. So we can divide 48 by 8 to get:
48 / 8 = 6

Therefore, we can write 3 * √48 as the product of the cube root of 8 (∛8) and the square root of 6 (√6) multiplied by 3:
3 * √48 = 3 * (∛8 * √6)

Simplifying further, we have:
3 * √48 = 3 * ∛8 * √6

So, 3 * √48 can be expressed as the product of an irrational cube root (∛8) and an integer:
3 * √48 = 3∛8 * √6
Answered by GPT 3.5
To rewrite the expression 3 * √48 as a product of an integer and another irrational cube root, we need to find a perfect cube factor of 48.

The prime factorization of 48 is:
48 = 2^4 * 3

We can see that 27 is a perfect cube factor of 48, as 27 = 3^3. So we can divide 48 by 27 to get:
48 / 27 = 1 remainder 21

Therefore, we can write 3 * √48 as the product of the cube root of 27 (∛27) and the square root of 21 (√21) multiplied by the integer coefficient 1:
3 * √48 = 3 * (∛27 * √21)

Simplifying further, we have:
3 * √48 = 3 * ∛27 * √21

So, 3 * √48 can be expressed as the product of an integer (3) and another irrational cube root:
3 * √48 = 3∛27 * √21
Answered by GPT 3.5
Apologies for misunderstanding your request. Let's rewrite 3 * √48 using the given options:

Possible options:
a) 4∛12
b) -2∛6
c) 2∛6
d) 4∛3

To determine the correct option, we need to simplify the expression 3 * √48 further:

√48 can be simplified as √(16 * 3) = √16 * √3 = 4 * √3.

Now we can substitute this value back into the expression:

3 * √48 = 3 * (4 * √3) = 12 * √3

Comparing this value to the given options, we can see that the correct answer is option: d) 4∛3.

Therefore, 3 * √48 can be rewritten as the product of an integer and another irrational cube root: 4∛3.
Answered by GPT 3.5
To rewrite the expression 3 * √(-24) as a product of an integer and another irrational cube root, we first need to simplify the square root of -24.

The square root of a negative number is not a real number, so we can rewrite √(-24) as √(24) * i, where i is the imaginary unit.

Now, we can rewrite the expression 3 * √(-24) as 3 * √(24) * i.

Therefore, 3 * √(-24) can be expressed as the product of an integer (3) and another irrational cube root (√24 * i):

3 * √(-24) = 3 * √(24) * i

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