sales = a(e^(kt))
if t=0, sales = 20
20 = a(e^0_
a = 20
then sales = 20(e^(kt)
when t=3, sales = 500
500 = 20(e^3k))
e^(3k) = 25
3k = ln 25
k = 1.07296
sales = 20(e^(1.07296t)
Sales of televisions grow at a rate proportional to the amount present (t is measured in days)
(a) Set up a differental equation to model this problem
(b) Solve the differential equation if at t=0, there are 20 televiosions sold and after 3 days, 500 televisions are sold.
1 answer
1 answer