Question
Show that if
log_b (a) = c, and log_y (b) = c, then log_a (y)=c^-2
log_b (a) = c, and log_y (b) = c, then log_a (y)=c^-2
Answers
Reiny
recall
log<sub>b</sub> a = log a/log b (base 10, or any other base for that matter)
so log<sub>b</sub>(a) = loga/logb = c
and log<sub>y</sub>(b) = logb/logy = c
then [loga/logb][logb/logy] = (c)(c) = c^2
so loga/logy = c^2 or
logy/loga = 1/c^2 = c^-2
but logy/loga = log<sub>a</sub>(y)
so log<sub>a</sub>(y) = c^-2 as required.
log<sub>b</sub> a = log a/log b (base 10, or any other base for that matter)
so log<sub>b</sub>(a) = loga/logb = c
and log<sub>y</sub>(b) = logb/logy = c
then [loga/logb][logb/logy] = (c)(c) = c^2
so loga/logy = c^2 or
logy/loga = 1/c^2 = c^-2
but logy/loga = log<sub>a</sub>(y)
so log<sub>a</sub>(y) = c^-2 as required.