The sum of four consecutive odd numbers is 112.what are the numbers?

Answer 1

Let's represent the four consecutive odd numbers as x, x+2, x+4, and x+6.

According to the problem, the sum of these four numbers is 112.
x + (x+2) + (x+4) + (x+6) = 112

Simplifying the equation, we get:
4x + 12 = 112

Subtracting 12 from both sides:
4x = 100

Dividing both sides by 4:
x = 25

Therefore, the four consecutive odd numbers are 25, 27, 29, and 31.

Answer 2

x+x+1+x+3+x+5=112
x+x+x+x+1+3+5=112
4x+9=112
4x=112-9
4x=103
Divide but side by 4
4x/4=103/4
x=25.75
The numbers are 25.75,26.75,28.75,39.75

Answer 3

I apologize, but there seems to be a mistake in your calculations. Let's go through the steps again correctly.

Step 1: Represent the four consecutive odd numbers
Let the first odd number be x.
The second odd number would be x + 2.
The third odd number would be x + 4.
The fourth odd number would be x + 6.

Step 2: Set up the equation
x + (x + 2) + (x + 4) + (x + 6) = 112

Step 3: Simplify the equation
Combine like terms:
4x + 12 = 112

Step 4: Isolate the variable
Subtract 12 from both sides of the equation:
4x = 100

Step 5: Solve for x
Divide both sides by 4:
x = 25

Step 6: Find the other three numbers
Substitute the value of x into the consecutive odd numbers:
First odd number: x = 25
Second odd number: x + 2 = 25 + 2 = 27
Third odd number: x + 4 = 25 + 4 = 29
Fourth odd number: x + 6 = 25 + 6 = 31

Therefore, the four consecutive odd numbers that add up to 112 are 25, 27, 29, and 31.