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the perimeter of the square is 204 ft. what is the value of x if 1 side of the square is 5x+6 ft
16 years ago

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Reiny
then
(5x+6)(5x+6) = 204
(5x+6)^2 = 204
5x+6 = ± √204 but x is sureley positive, so
x = (√204 - 6)/5 = (2√51 - 6)/5 or appr. 1.6567
16 years ago
Ms. Sue
204 / 4 = 51

5x + 6 = 51
5x = 45
x = ?
16 years ago
Reiny
silly me, read the question wrong and made it harder than it had to be.
16 years ago

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