A body of mass 5 kg moving with a velocity of 20meter per second square hits stationary body of mass 3kg. If they move together after collisions with a velocity v, find the velocity v

1 answer

To find the velocity v after the collision, we can use the principle of conservation of momentum.

Before the collision, the momentum of the 5 kg body is given by:
momentum1 = mass1 * velocity1 = 5 kg * 20 m/s = 100 kg m/s

Since the other body is stationary, its momentum before the collision is zero:
momentum2 = mass2 * velocity2 = 0

The total momentum before the collision is given by the sum of the momenta of the two bodies:
total momentum before = momentum1 + momentum2 = 100 kg m/s + 0 = 100 kg m/s

After the collision, the two bodies move together as one object with mass m = mass1 + mass2:
m = 5 kg + 3 kg = 8 kg

Let v be the velocity of the two bodies after the collision.
The total momentum after the collision is given by the mass of the combined bodies multiplied by the velocity:
total momentum after = m * v

According to the conservation of momentum principle, the total momentum before and after the collision should be equal:
total momentum before = total momentum after
100 kg m/s = 8 kg * v
v = 100 kg m/s / 8 kg
v = 12.5 m/s

Therefore, the velocity v after the collision is 12.5 m/s.