Question

Use any method to locate the zeros of y = -3x^2 +12x + 15.
• (1,0) (-5,0)
• There are no zeros
• (0,15)
• (-1,0) (5,0)

Answer 1

To find the zeros of the equation y = -3x^2 + 12x + 15, we need to set y equal to zero and solve for x.

Setting y = 0, we get:
0 = -3x^2 + 12x + 15

Rearranging the equation, we have:
3x^2 - 12x - 15 = 0

Now we can factor the quadratic equation. Taking out a common factor of 3, we get:
3(x^2 - 4x - 5) = 0

Next, we can factor the quadratic expression in the parentheses:
3(x - 5)(x + 1) = 0

Now we have factored form, where each factor can be set equal to zero:
x - 5 = 0 or x + 1 = 0

Solving each equation, we find:
x = 5 or x = -1

Therefore, the zeros of the equation y = -3x^2 + 12x + 15 are (5, 0) and (-1, 0).