You have posted several questions which are all based on the same principles
already pointed out by 'drwls'
Why don't you make a diagram of a regular polygon, sketch the 5 isosceles triangles created by joining the vertices to the centre.
Wouldn't the central angle of each of those be 360/5º ? or 72º ?
now work your way around the whole figure by finding all the angles, including the exterior angles formed by extending the sides
I noticed 'drwls' already pointed out that the exterior angle is 360/(number of sides), in this case 360/5
Isn't that the same as the central angle?
Now repeat the argument for an n-sided regular polygon.
The exterior angle of a regular polygon is the angle formed by an extended side and the adjacent side.
c) How do the central angel and the exterior angle of a regular pentagon compare? Is this relationship true in any regular polygon? Explain.
Help
2 answers
You've received good ideas from two math teachers. Your other posts have therefore been removed.
If you have further questions, be sure to post what YOU HAVE DONE as well.
If you have further questions, be sure to post what YOU HAVE DONE as well.
1 answer