Asked by Anonymous
Solve for x.
x(x+3)=2^2
I think I'm doing this all wrong. Here is the work I've done so far:
x^2+3x=4
x^2+3x-4=0
...now what?
i started trying to use the equation x=-b sqrt of (b^2-4ac)
but I'm just getting confused...
x(x+3)=2^2
I think I'm doing this all wrong. Here is the work I've done so far:
x^2+3x=4
x^2+3x-4=0
...now what?
i started trying to use the equation x=-b sqrt of (b^2-4ac)
but I'm just getting confused...
Answers
Answered by
bobpursley
you can use that equation, but why not just factor it?
(x+4)(x-1)=0
that tells you x can be one, or minus four.
(x+4)(x-1)=0
that tells you x can be one, or minus four.