The slope of the line passing through $A$ and $B$ is
\[\frac{5 - 1}{-2 - (-3)} = \frac{4}{1} = 4.\]Therefore, the equation of this line is
\[y - 5 = 4(x + 2).\]In particular, $y = 5 + 4x.$
The slope of the line passing through $B$ and $C$ is
\[\frac{1 - y}{-3 - 4} = \frac{y - 1}{7} = 4.\]Thus, $4y - 4 = 7,$ so $4y = 11,$ and $y = \boxed{\frac{11}{4}}.$
A line passes through the points $A,$ $B,$ and $C.$ If $A = (-2,5),$ $B = (-3,1),$ and $C = (4,y),$ then find $y.$
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