A company owns two dealerships, both of which sell cars and trucks. Dealership A sells a total of 164 cars and trucks. Dealership B sells twice as many cars and half as many trucks as Dealership A, and sells a total of 229 cars and trucks.

(4 points)

a) An equation for the total cars and trucks for Dealership A

b) An equation for the total cars and trucks for Dealership B

c) How many cars did Dealership A sell?

d) Considering that Dealership B sold half as many trucks as Dealership A, how

many trucks did Dealership B sell?

1 answer

a) Let's denote the number of cars sold by Dealership A as x, and the number of trucks sold by Dealership A as y. Therefore, the equation for the total cars and trucks sold by Dealership A is x + y = 164.

b) Let's denote the number of cars sold by Dealership B as 2x (twice as many as Dealership A), and the number of trucks sold by Dealership B as (1/2)y (half as many as Dealership A). Therefore, the equation for the total cars and trucks sold by Dealership B is 2x + (1/2)y = 229.

c) From the equation for Dealership A, x + y = 164, we don't have enough information to determine how many cars Dealership A sold. We would need another equation or more information to solve for x.

d) From the equation for Dealership B, 2x + (1/2)y = 229, we cannot directly determine the number of trucks sold by Dealership B because we do not know the values of x and y. We would need another equation or more information to solve for (1/2)y.