A company owns two dealerships, both of which sell cars and trucks. Dealership A sells a total of 164 cars and trucks. Dealership B sells twice as many cars and half as many trucks as Dealership A, and sells a total of 229 cars and trucks.

(4 points)

a) An equation for the total cars and trucks for Dealership A

b) An equation for the total cars and trucks for Dealership B

c) How many cars did Dealership & sell?

d) Considering that Dealership E sold half as many trucks as Dealership A, how

many trucks did Dealership B sel?

1 answer

a) Let's represent the number of cars sold by Dealership A as "x" and the number of trucks as "y".

So, the equation for the total cars and trucks for Dealership A is:

x + y = 164

b) According to the given information, Dealership B sells twice as many cars and half as many trucks as Dealership A. So, the equation for the total cars and trucks for Dealership B is:

2x + (1/2)y = 229

c) To find the number of cars sold by Dealership A, we can use the equation x + y = 164. Since we're only interested in the number of cars, we can solve for x as follows:

x = 164 - y

d) Considering that Dealership B sold half as many trucks as Dealership A, we can represent the number of trucks sold by Dealership B as (1/2)y. So, the number of trucks sold by Dealership B is (1/2)y.