Asked by gnozahs
Xrays with a wavelenth of 1.70A scatter at an angle of 21.5 degrees from a crystal. If n=1, what is the distance between planes of atoms in the crystal that give rise to this scatterying?
So far I've gotten .367 radians but I have no idea where to go from there.
So far I've gotten .367 radians but I have no idea where to go from there.
Answers
Answered by
DrBob222
n*lambda = 2d*sin theta.
solve for d.
solve for d.
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