Question
a plane inclined at an angle of 30 degrees to the horizontal has an efficiency of 50% what is the force required to push a load of 120N up the plane
Answers
GPT 3.5
To find the force required to push the load up the plane, we need to calculate the component of the weight of the load that acts parallel to the inclined plane.
First, let's find the weight of the load. The weight is given as 120N.
The weight of an object is the force acting on it due to gravity, which is given by the formula:
Weight = mass * acceleration due to gravity
To find the weight, we need to know the mass of the load and the acceleration due to gravity. The acceleration due to gravity is approximately 9.8 m/s².
Weight = 120N
120N = mass * 9.8 m/s²
Dividing both sides of the equation by 9.8 m/s², we get:
mass = 120N / 9.8 m/s²
mass = 12.24 kg
Now that we know the mass of the load is 12.24 kg, we can calculate the component of its weight that acts parallel to the inclined plane. This component is given by the formula:
Parallel Force = Weight * sin(angle of inclination)
Plugging in the values:
Parallel Force = 12.24 kg * 9.8 m/s² * sin(30 degrees)
Parallel Force = 12.24 kg * 9.8 m/s² * 0.5
Parallel Force = 60.18 N (rounded to two decimal places)
Therefore, the force required to push the load of 120N up the inclined plane is approximately 60.18N.
First, let's find the weight of the load. The weight is given as 120N.
The weight of an object is the force acting on it due to gravity, which is given by the formula:
Weight = mass * acceleration due to gravity
To find the weight, we need to know the mass of the load and the acceleration due to gravity. The acceleration due to gravity is approximately 9.8 m/s².
Weight = 120N
120N = mass * 9.8 m/s²
Dividing both sides of the equation by 9.8 m/s², we get:
mass = 120N / 9.8 m/s²
mass = 12.24 kg
Now that we know the mass of the load is 12.24 kg, we can calculate the component of its weight that acts parallel to the inclined plane. This component is given by the formula:
Parallel Force = Weight * sin(angle of inclination)
Plugging in the values:
Parallel Force = 12.24 kg * 9.8 m/s² * sin(30 degrees)
Parallel Force = 12.24 kg * 9.8 m/s² * 0.5
Parallel Force = 60.18 N (rounded to two decimal places)
Therefore, the force required to push the load of 120N up the inclined plane is approximately 60.18N.