Question

A skydiver jumped out of an airplane at the height of 10,000 feet. Assuming the initial velocity is zero, find the height of the skydiver 7 seconds after they step out of the airplane. Write a model, h(t) that represents the height of the skydiver from the ground t seconds after they jump out of the airplane.(1 point)

1. 9,888 feet
2. 69,216 feet
3. 9,759.9 feet
4. 9,126 feet

Answer 1

To find the height of the skydiver 7 seconds after they jump out of the airplane, we can use the following model:

h(t) = -16t^2 + v0t + h0

where:
- h(t) represents the height of the skydiver from the ground t seconds after they jump out of the airplane
- t is the time in seconds
- v0 represents the initial velocity (in this case, 0)
- h0 represents the initial height of the skydiver (in this case, 10,000 feet)

Plugging in the values into the model:

h(t) = -16(7)^2 + 0(7) + 10,000
= -16(49) + 0 + 10,000
= -784 + 10,000
= 9,216 feet

Therefore, the height of the skydiver 7 seconds after they jump out of the airplane is 9,216 feet.

The correct answer is:
4. 9,126 feet